Let's Have a Funny Pic Thread! Mk 35

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shoeless said:
One of the toughest math-related puzzles I've ever come across below. Yes, there is enough information here to find a single solution.

There are three brothers. The product of their ages is 36. The sum of their ages is equal to the age of their only sister. The three brothers never admit their ages, but their sister always admits her own. Even so, you need to know that the oldest brother usually wears his baseball cap backward. How old is each brother?​
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I'm going to need an explanation on how there is a single solution. Seems to me that there are a number of solutions.

I assume that the intent of saying "oldest" brother means that the oldest brother is older than the other two by at least a full year, even though that is not stated. I'll also assume that the sum and product are expected to be generated from the integer yearly age, not the fractional age.

B1 = 1, B2 = 1, B3 = 36, S = 38
B1 = 1, B2 = 2, B3 = 18, S = 21
B1 = 1, B2 = 3, B3 = 12, S = 16
B1 = 1, B2 = 4, B3 = 9, S = 14
B1 = 2, B2 = 2, B3 = 9, S = 13
B1 = 2, B2 = 3, B3 = 6, S = 11

And the list repeated with B1 and B2 swapped.
 
GomezAddams said:
I'm going to need an explanation on how there is a single solution. Seems to me that there are a number of solutions.

I assume that the intent of saying "oldest" brother means that the oldest brother is older than the other two by at least a full year, even though that is not stated. I'll also assume that the sum and product are expected to be generated from the integer yearly age, not the fractional age.

B1 = 1, B2 = 1, B3 = 36, S = 38
B1 = 1, B2 = 2, B3 = 18, S = 21
B1 = 1, B2 = 3, B3 = 12, S = 16
B1 = 1, B2 = 4, B3 = 9, S = 14
B1 = 2, B2 = 2, B3 = 9, S = 13
B1 = 2, B2 = 3, B3 = 6, S = 11

And the list repeated with B1 and B2 swapped.
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Glad you wrote it out, was trying to decide if I could be bothered. List also needs to include B1 =3, B2=3, B3=4, S= 10.

As anyone can wear a baseball backwards if they like at any age, the question is short on information but I'm hazarding a guess that a catcher in baseball would normally wear their cap backwards for visibility? Is that right and are there any age implications for that in the schools over there in the US?
 
Gorgon90 said:
Glad you wrote it out, was trying to decide if I could be bothered. List also needs to include B1 =3, B2=3, B3=4, S= 10.

As anyone can wear a baseball backwards if they like at any age, the question is short on information but I'm hazarding a guess that a catcher in baseball would normally wear their cap backwards for visibility? Is that right and are there any age implications for that in the schools over there in the US?
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Catchers don't wear caps. They wear batting helmets backwards. Kinda hard to wear a mask with the bill forward.

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GomezAddams said:
I'm going to need an explanation on how there is a single solution. Seems to me that there are a number of solutions.

I assume that the intent of saying "oldest" brother means that the oldest brother is older than the other two by at least a full year, even though that is not stated. I'll also assume that the sum and product are expected to be generated from the integer yearly age, not the fractional age.

B1 = 1, B2 = 1, B3 = 36, S = 38
B1 = 1, B2 = 2, B3 = 18, S = 21
B1 = 1, B2 = 3, B3 = 12, S = 16
B1 = 1, B2 = 4, B3 = 9, S = 14
B1 = 2, B2 = 2, B3 = 9, S = 13
B1 = 2, B2 = 3, B3 = 6, S = 11

And the list repeated with B1 and B2 swapped.
Click to expand...
Might want to double check that list. You may have missed some possible combinations...and when I say "may have"...well, you did. :wink: You're on the right track though, and once you get the complete list, the answer will reveal itself. And yes, integer yearly age only.
 
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